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December 18, 2014

December 18, 2014

Posted by **bailey** on Sunday, April 4, 2010 at 8:06pm.

- algebra 2 -
**Brennen**, Sunday, April 4, 2010 at 8:14pmIf I remember correctly, you would log both sides of the equation to and move the 2x to the front. so it would be 2xLOG5=3. Does that work? If not sorry.

- algebra 2 -
**bailey**, Sunday, April 4, 2010 at 8:33pmI thought you would do guess and check

but i have no idea

- algebra 2 -
**Brennen**, Sunday, April 4, 2010 at 8:43pmdo you understand what i did?

- algebra 2 -
**Damon**, Sunday, April 4, 2010 at 9:04pm2 x log 5 = LOG 3

- algebra 2 -
**bailey**, Sunday, April 4, 2010 at 9:15pmwhat is X???

- algebra 2 -
**Brennen**, Sunday, April 4, 2010 at 10:11pmuse your calculator and solve for it

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