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December 18, 2014

December 18, 2014

Posted by **Abbey** on Sunday, April 4, 2010 at 5:30pm.

a1 = 2 r=sqrt3

I know the first term is 2 but the sqrt 3 threw me off so I do not know how to find the next numbers.

2) Find the nth term of the geometric sequence.

a2 = 3 a5 = 3/64 n=1

I know the formula is a1^r n-1 but I do not know how to find a1.

- Pre-Cal -
**drwls**, Sunday, April 4, 2010 at 5:42pm1) a1 = 2

a2 = 2 sqrt3

a3 = 2sqrt3*sqrt3 = 6

a4 = 6*sqrt3

a5 = 6 sqrt3*sqrt2 = 18

2) an = 3*4/4^(n-1)

a1 = 3*4/4^0 = 12

a2 = 3

a3 = 3/4

a4 = 3/16

a5 = 3/64

- Pre-Cal -
**Abbey**, Sunday, April 4, 2010 at 5:46pmThank You

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