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April 18, 2014

April 18, 2014

Posted by **johnica martin** on Sunday, April 4, 2010 at 4:56pm.

Log7 x= ½ log7 36 (log base 7)

log x=2log 5+ log 4

Logx 10 + logx 8-logx 5= 4 (log base x)

5^2x=3

- Math -
**Damon**, Sunday, April 4, 2010 at 5:16pmLog7 x= ½ log7 36 (log base 7)

log7 (x) = log7 (36)^.5

so

x = 36^.5 = 6

- Math -
**Damon**, Sunday, April 4, 2010 at 5:17pmlog x=2log 5+ log 4

log x = log(5)^2 + log 4

log x = log (25*4)

x = 100

- Math -
**Damon**, Sunday, April 4, 2010 at 5:20pmLogx 10 + logx 8-logx 5= 4 (log base x)

logx (10*8/5) = 4

logx (16) = 4

16 = x^4

well, what to the fourth power = 16 ?

- Math -
**Damon**, Sunday, April 4, 2010 at 5:22pm5^2x=3

2 x log 5 = log 3

x log 25 = log 3

x = log 3 / log 25

- Math -
**johnica martin**, Sunday, April 4, 2010 at 5:52pmi have this problem ½ log2 x=3log22-log24

(log base 2) it is kinda of the same as the first one but i dont undersand how you got them?

- Math -
**Damon**, Sunday, April 4, 2010 at 6:01pmlog2 (x^.5 ) = log2 (8) - log2(4)

log2 (x^.5) = log2 (2) which is 1

log 2 (x^.5) = 1

x^.5 = 2^1 = 2

x = 2^2 = 4

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