how do i go about in solving this?
A helium atom (mass 4.0 u) moving at 596 m/s to the right collides with an oxygen molecule (mass 32 u) moving in the same direction at 402 m/s. After the collision, the oxygen molecule moves at 445 m/s to the right. What is the velocity of the helium atom after the collision?
physics - Damon, Sunday, April 4, 2010 at 5:25pm
total momentum before collision to the right=
4*596 + 32*402
total momentum to the right after collision=
4*v + 32*445
total momentum after = total momentum before so solve for v