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December 19, 2014

December 19, 2014

Posted by **Abbey** on Sunday, April 4, 2010 at 3:59pm.

a1 = 2 r=sqrt3

I know the first term is 2 but the sqrt 3 threw me off so I do not know how to find the next numbers.

2) Find the nth term of the geometric sequence.

a2 = 3 a5 = 3/64 n=1

I know the formula is a1^r n-1 but I do not know how to find a1.

- Pre-Cal(Please help) -
**Abbey**, Sunday, April 4, 2010 at 5:46pmAnswered Already

- Pre-Cal(Please help) -
**Damon**, Sunday, April 4, 2010 at 5:49pm2

2 sqrt 3

2*3 = 6

6 sqrt 3

6*3 = 18

18 sqrt 3

18*3 = 54 etc

- Pre-Cal(Please help) -
**Damon**, Sunday, April 4, 2010 at 5:57pma1

a1 r = 3

a1 r^2

a1 r^3

a1 r^4 = 3/64

so

a1 = 3/r

( 3 r^4/r) = 3/64

r^3 = 1/64 = 1/2^6

r = 1/2^2

r = 1/4

a1 = 12

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