Wednesday

March 4, 2015

March 4, 2015

Posted by **Anonymous** on Saturday, April 3, 2010 at 8:21am.

- Calculus -
**bobpursley**, Saturday, April 3, 2010 at 9:16amdraw the figure, at noon, then at 4PM.

At 4 pm, I have a right triangle of A,B of sides (base 10+19*4; altitude 15*4)

d^2=(10+va*t)^2 + (vb*t)^2

2d dd/dt=2(10*va*t)va+2(vb*t)vb

so when t=4, solve for dd/dt

- Calculus -
**Anonymous**, Tuesday, October 5, 2010 at 9:11pm9898

- Calculus -
**Anonymous**, Sunday, October 12, 2014 at 6:34pmkhj

**Answer this Question**

**Related Questions**

Calculus - At noon, ship A is 50 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...

CALCULUS - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...

Calculus - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...

Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

calculus 1 - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...

calculus 1 - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...