Homework Help: chemistry(check my work)

Posted by eng on Saturday, April 3, 2010 at 1:01am.

If 6.01 g of K2SO3 dissolved in 930 mL of water reacts stoichiometrically according to the balanced equation in a reaction solution with a total volume of 990 mL, what is the molarity (M) of KCl produced?

K2SO3(aq) + 2 HCl(aq) → SO2(g) + 2KCl(aq) + H2O(l)

6.01gx molecular weigt of K2SO3=mole of K2SO3
mole of K2SO3x2=mole of KCL
mole of KCL/.99L=M

chemistry(check my work) - DrBob222, Saturday, April 3, 2010 at 1:09am
No.
6.01 g/molar mass K2SO4 = moles K2SO3.
moles KCl = 2x that.
(KCl) = mols/0.99

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