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chemistry

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If 0.0490 mol of solid Al reacts stoichiometrically according to the balanced equation with 990 mL of aqueous Cl-, what molarity (M) of Cl- is required?

3 CuCl2(aq) + 2 Al(s) → 3 Cu + 2AlCl3(aq)

  • chemistry - ,

    You have 0.0490 mole Al.
    I assume that is 990 mL aq CuCl2. Moles CuCl2 needed = moles Al x (3 moles CuCl2/2 moles Al) = ??
    M CuCl2 = moles/L = ?? moles/0.990 L.
    The Cl^- must be 2x that. Check my thinking.

  • chemistry - ,

    i did 0.049x2/3=mole of CuCl2
    then mole of cucl2/.99 then times by 2 to get 0.0660 but its wrong, the actual answer is 0.148. Can you double check this again why i did it wrong

  • chemistry - ,

    You messed up on the conversion. Look at my response again. It is 0.049 x (3/2) and that x 2 and NOT 0.049 x (2/3) and that x 2. ;-).
    I don't get 0.148 but 0.1470000000000.

  • chemistry - ,

    Sorry about that. I forgot to divide by 0.99 and the answer is 0.148. But your error still is the same. Multiply by 3/2 and not by 2/3.

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