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Chromium (II) nitrate forms a hydrate that is 40.50% water by mass. What is its chemical formula?

I just need to figure out how to do it!

  • Chemistry -

    Cr(NO3)2.xH2O. You want to determine the value of x.

    Take a 100 g sample which will give you
    40.5 g H2O and
    59.5 g Cr(NO3)2

    Convert to moles.
    40.5/molar mass H2O = ??
    59.5/molar mass Cr(NO3)2

    Now find the ratio of H2O molecules to 1 molecule Cr(NO3)2.
    Check your numbers; this doesn't come out as well as I think it should. Check my work; perhaps I made an error.

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