Friday

March 6, 2015

March 6, 2015

Posted by **Adrianne** on Thursday, April 1, 2010 at 7:53pm.

an altitude h = [03] km above the earth's surface and has a mass

m = 3500 kg. You wish to calculate when the satellite will be back in the same position. From the second law of

motion and the gravitational force law, calculate the following:

(a) What is the satellite's velocity? (m/s)

(b) What is the period of the satellite's motion?

The only force acting on the satellite is the force of gravity (Fg) right? So by combining the two laws I have Fg = ma. I solved for Fg, but I need some pointers on where to go from there.

- Physics -
**Damon**, Thursday, April 1, 2010 at 8:28pmmass is m (it will not matter in the end)

if height above earth is h

then radius of orbit = r = Rearth + h

then

Fg = G m Mearth/r^2

a = v^2/r

so Fg = m v2/r

so

G m Mearth/r^2 = m v^2/r

note m cancels, feather drifts right beside the space station

G Mearth/r = v^2

there you go

get v then it goes 2 pi r at v

**Answer this Question**

**Related Questions**

physics - 3. A satellite of mass 500 kg orbits the Earth with a period of 6000 s...

physics - A satellite has a mass of 100 kg and is in an orbit at 2.00*10^6 m ...

physics - How much work is required to lift a 600-kg satellite to an altitude of...

Physics - A satellite is orbiting the earth just above its surface. The ...

physics - Calculate the value of g for a satellite that is orbiting in a circle ...

Physics - A satellite moves in a circular orbit around the Earth at a speed of ...

physics - A satellite moves in a circular orbit around the Earth at a speed of 6...

Physics - A satellite moves in a circular orbit around the Earth at a speed of 5...

Physics - A satellite moves in a circular orbit around the Earth at a speed of 5...

physics - A satellite moves in a circular orbit around the Earth at a speed of 5...