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March 29, 2015

March 29, 2015

Posted by **john peaterson** on Thursday, April 1, 2010 at 6:38pm.

5+sinx-3cosx and state the value of x for which this maximum occurs

- MATHS>>>PLEASE HELP -
**Damon**, Thursday, April 1, 2010 at 7:20pmy = 5 + sin x - 3 cos x

dy/dx = 0 at min or max = cos x + 3 sin x

cos x = - 3 sin x

tan x = -1/3

x = -18.4 deg

that is in quadrants 2 and 4

x = 161.6 and 341.6 degrees

at 161.6

5 + sin x -3 cos x =5.27

at 341.6

5 + sin x -3 cos x = 4.64

looks like at 161.6 degrees for max

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