The number of accidents that occur at the intersection

of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?

To graph the probability distribution, we'll represent the number of accidents on the x-axis and the probability on the y-axis.

Number of Accidents (x-axis):
0 | 1 | 2 | 3

Probability (y-axis):
0.84 | 0.13 | 0.02 | 0.01

To calculate the expected value for a random variable, we multiply each value of the variable by its corresponding probability and then sum them up. In this case, the random variable is the number of accidents, and its values are 0, 1, 2, and 3.

Expected Value = (0 * 0.84) + (1 * 0.13) + (2 * 0.02) + (3 * 0.01)

Expected Value = 0 + 0.13 + 0.04 + 0.03

Expected Value = 0.20

Therefore, the expected value for the random variable, given the number of accidents, is 0.20.