If 50.0mL of 1.60M HCl was added to 50.0mL of 1.80M NaOH, calculate the molarity of the resulting NaCl solution. (Hint: resulting solution has a volume of 100 mL)
moles HCl = M x L
moles NaOH = M x L
Determine moles NaCl formed, then
M NaCl = moles/L
How do you determine the moles of just NaCl? and is the moles of HCl and NaOH just the molar mass? Thanks
You aren't following instructions.
moles HCl = M x L. You have molarity given in the problem as well as liters (actually milliliters and you convert to liters).
moles NaOH = M x L.
HCl + NaOH ==> NaCl + H2O
The equation tells you that 1 mol HCl reacts with 1 mol NaOH to produce 1 mol NaCl. You look at moles HCl and moles NaOH you have and based on the above ratio you decide how many moles NaCl are formed. (One of the materials is a limiting reagent). Then from moles NaCl formed, divide by L of solution (50 mL + 50 mL = 100 mL = 0.100 L) to get M which is moles/L.
.006M NaCl
How do you know that the NaCl has 100 ml. How much volume does the water which is also a product have?
If you are struggling with these kinds of questions ,, that means you are not trying to understand chemistry!! Just try to understand like a maths!!
To solve this problem, we can use the concept of the molarity formula, which states that:
Molarity (M) = moles of solute / volume of solution in liters.
First, we need to find the moles of HCl and NaOH that are added to the solution.
To find the moles of HCl, we can use the formula:
moles = concentration (M) x volume (L)
moles of HCl = 1.60 M x 0.050 L
moles of HCl = 0.08 moles
Similarly, for NaOH:
moles of NaOH = 1.80 M x 0.050 L
moles of NaOH = 0.09 moles
Since HCl and NaOH react in a 1:1 molar ratio, the moles of NaOH consumed will be equal to the moles of NaCl formed in the reaction.
Therefore, the moles of NaCl formed = 0.09 moles.
Next, we need to find the molarity of the resulting NaCl solution.
Molarity (M) = moles of solute / volume of solution in liters
Since the volume of the resulting NaCl solution is given as 100 mL, we need to convert it to liters by dividing by 1000:
Volume of solution = 100 mL / 1000 = 0.100 L
Finally, we can calculate the molarity of the NaCl solution:
Molarity (M) = moles of NaCl / volume of solution in liters
Molarity (M) = 0.09 moles / 0.100 L
Molarity (M) = 0.9 M
Therefore, the molarity of the resulting NaCl solution is 0.9 M.