Posted by **Tyga** on Thursday, April 1, 2010 at 10:41am.

On a TV game show, the contestant is asked to select a

door and then is rewarded with the prize behind the door

selected. If the doors can be selected with equal probability,

what is the expected value of the selection if the

three doors have behind them a $40,000 foreign car, a $3

silly straw, and a $50 mathematics textbook?

- MATH 157 -
**Reiny**, Thursday, April 1, 2010 at 11:41am
Each door has a prob of 1/3

expected value

= 1/3( 40000 + 3 + 50 ) = 13351

- MATH 157 -
**Ty**, Thursday, April 1, 2010 at 1:00pm
How did you get this answer I want to make sure im doing this correctly, thank you.

- MATH 157 -
**Reiny**, Thursday, April 1, 2010 at 1:05pm
expected return on picking first door

= (1/3)(4000)

expected return on second door

= (1/3)(3)

expected return on third door

= (1/3)50)

so expected return on whole event

= (1/3)(4000) + (1/3)(3) + (1/3)(50)

= (1/3)( 40000 + 3 + 50 ) = 13351 as above

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