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September 30, 2014

September 30, 2014

Posted by **bindiya farswani** on Thursday, April 1, 2010 at 10:06am.

Please correct me if I'm wrong.

- math -
**Reiny**, Thursday, April 1, 2010 at 10:25am3x^2 + 6x +3 =0

first divide each term by 3, the fact that the right side is zero and zero divided by anything is zero, we can just drop the 3

x^2 + 2x + 1 = 0

(x+1)^2 =

take √ of both sides

x+1 = 0

x = -1

You had it factored correctly, but you "lost " your equation by dropping the =0 part.

- math -
**bindiya farswani**, Thursday, April 1, 2010 at 10:30amOh, thanks a lot!

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