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August 22, 2014

August 22, 2014

Posted by **Anonymous** on Thursday, April 1, 2010 at 8:55am.

a)Determine the number of grams in 0.750 moles of the compound Iron(II)phosphate: Fe3(PO4)2.

answer: 129.68grams 357.477722g/mol is correct?

b)How many atoms of iron are in 0.750 moles of the compound

Iron(III)oxide?

Answer: .75 x 6.0220 10^23 = 5.5165 is correct answer?

- Chemistry -
**DrBob222**, Thursday, April 1, 2010 at 11:52amNeither is correct.

If you re-read what I wrote last night,

grams = moles x molar mass. If I plug in 0.75 for moles and 357.48 for molar mass, I don't get 129.68. As I told you last night, your problem isn't chemistry, it's punching in the right keys on your calculator.

For the second problem you need to go back and read the original instructions.

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