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February 1, 2015

February 1, 2015

Posted by **Judy and group** on Thursday, April 1, 2010 at 5:30am.

observations and found the mean x = 106 and the standard deviation sx = 35. The value of the test

statistic is equal to

(1) 1.1743

(2) −1.7143

(3) 0.1714

(4) 17.143

(5) 1.7143

ANSWER:1

18-Suppose we want to test the null hypothesis H0 : ́ = 400 against H1 :́ < 400. The test statistic is

calcuated as −1.23 and the two-tailed critical value is 1.96. The appopriate p–value will be

(1) −0.0500

(2) 0.3907

(3) 0.1093

(4) 0.8907

(5) −0.1093

ANSWER: 3

19- Determine the p–value associated with the values of the standardized test statistic z = 1.05 for one-tail

test.

(1) 0.3531

(2) 0.1469

(3) 0.8531

(4) 0.0146

(5) 0.2938

ANSWER: 3

20-Using the confidence interval when conducting a two-tail test for the population mean, we do not reject

the null hypothesis if the hypothesized value:

(1) is to the left of the lower confidence limit

(2) is to the right of the upper confidence limit

(3) falls between the lower and upper confidence limits

(4) falls in the rejection region

(5) all the above statements are correct

ANSWER: 3

- STATS (PLEASE CHECK) -
**PsyDAG**, Thursday, April 1, 2010 at 10:32am16. Your fail to indicate your sample size to determine the standard error of the mean. SE = SD/√(n-1) is needed to determine the significance of difference between means.

However, it seems like the alternatives are using the SD rather than SE. Then Z = (x - μ)/SD =

(106-100)/35 = 6/35 = .1714

18. Your H1 indicates a one-tailed test, but you are using a two-tailed critical value. I'm not sure what you are looking for with the "p-value." If this is probability of Alpha error, then .1093 is correct.

19. I'm not sure what you are looking for with the "p-value." If this is probability of Alpha error, then .1469 is correct.

20. Correct

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