If 50.0mL of 1.60M HCl was added to 50.0mL of 1.80M NaOH, calculate the molarity of the resulting NaCl solution. (Hint: resulting solution has a volume of 100 mL)
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No of moles of aspirin = No of mole of NaOH – No of mole of HCl
(M x V) NaOH – (M x V) HCl
(0.1M x 21.20ml) – (0.04M x 21.80ml)
1.248mmoles
Mass of aspirin = 180.157g/mol x 1.248mmoles = 224.8359mg
224.8359mg x 1g/1000mg = 0.2248g of Aspirin
Since, 0.102g Aspirin powder contains 0.2248 aspirin, what is the mass percent of aspirin in the tablet?
0.2248g/0.300g x 100 = 74.9%
To calculate the molarity of the resulting NaCl solution, we need to use the concept of stoichiometry and the equation for the reaction between HCl and NaOH.
The balanced chemical equation for the reaction is:
HCl + NaOH → NaCl + H2O
From the equation, we see that 1 mole of HCl reacts with 1 mole of NaOH, resulting in 1 mole of NaCl.
First, let's calculate the number of moles of HCl and NaOH in the given volumes:
For HCl:
Molarity (M) = moles/volume (L)
1.60 M = moles HCl / 0.0500 L (50.0 mL converted to L)
moles HCl = 1.60 M * 0.0500 L
For NaOH:
Molarity (M) = moles/volume (L)
1.80 M = moles NaOH / 0.0500 L (50.0 mL converted to L)
moles NaOH = 1.80 M * 0.0500 L
Since the reaction is 1:1, the moles of NaOH are equal to the moles of NaCl in the resulting solution.
Now, let's calculate the total volume of the resulting solution by adding the volumes of HCl and NaOH:
Total volume = 50.0 mL + 50.0 mL = 100 mL (converted to L)
Finally, we can calculate the molarity of the resulting NaCl solution:
Molarity (M) = moles NaCl / volume (L)
Molarity (M) = moles NaOH / 0.100 L (100 mL converted to L)
Substituting the values we calculated earlier:
Molarity (M) = (1.80 M * 0.0500 L) / 0.100 L
Simplifying the equation gives us the molarity of the resulting NaCl solution.