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Chemistry

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If 50.0mL of 1.60M HCl was added to 50.0mL of 1.80M NaOH, calculate the molarity of the resulting NaCl solution. (Hint: resulting solution has a volume of 100 mL)

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    http://www.jiskha.com/display.cgi?id=1270133730

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    55

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    No of moles of aspirin = No of mole of NaOH – No of mole of HCl
    (M x V) NaOH – (M x V) HCl
    (0.1M x 21.20ml) – (0.04M x 21.80ml)
    1.248mmoles
    Mass of aspirin = 180.157g/mol x 1.248mmoles = 224.8359mg
    224.8359mg x 1g/1000mg = 0.2248g of Aspirin
    Since, 0.102g Aspirin powder contains 0.2248 aspirin, what is the mass percent of aspirin in the tablet?
    0.2248g/0.300g x 100 = 74.9%

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    :P

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