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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Wednesday, March 31, 2010 at 11:41pm.

a)Determine the number of grams in 0.750 moles of the compound Iron(II)phosphate: Fe3(PO4)2.

Answer: ?

b)How many atoms of iron are in 0.750 moles of the compound

Iron(III)oxide?

Answer: ?

- Chemistry -
**DrBob222**, Wednesday, March 31, 2010 at 11:50pmAnd it will never be your thing if we give you the answers.

a. g = moles x molar mass Remember this one formula and you can rearrange it to give you three things, depending upon the question.

a. grams = moles x molar mass

b. moles = grams/molar mass

c. molar mass = grams/moles.

There is no chemistry involved. This is just a little algebra.

b. There are 6.022 x 10^23 molecules in a mole of anything so 0.75 x 6.022 x 10^23 = the number of molecules of iron(III) oxide. The formula for iron(III) oxide is Fe2O3. You know how many molecules are there and there are _______ atoms in 1 molecule of Fe2O3 so there are _____ in 0.75 mole Fe2O3.

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