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March 2, 2015

March 2, 2015

Posted by **hr** on Wednesday, March 31, 2010 at 9:12pm.

28) 5’8"–6’

29) 5’6"–6’2"

30) Above 5’10"

31) Below 6’

32) Above 5’8"

33) 5’8"–6’4"

- statistics -
**PsyDAG**, Thursday, April 1, 2010 at 11:17amZ = # of SD away from the mean = (x - mean)/SD

Calculate the Z score values for each height. Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions desired. Multiply that proportion by 1000.

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