How many moles of chlorine are needed to react with 3.30 moles of aluminum?
You need an equation.
To determine the number of moles of chlorine needed to react with aluminum, we first need to write a balanced chemical equation for the reaction between aluminum and chlorine.
The balanced chemical equation for the reaction between aluminum (Al) and chlorine (Cl₂) is:
2 Al + 3 Cl₂ -> 2 AlCl₃
According to the balanced chemical equation, 2 moles of aluminum react with 3 moles of chlorine to produce 2 moles of aluminum chloride.
Now, we can use the stoichiometry of the balanced equation to determine the number of moles of chlorine needed to react with 3.30 moles of aluminum.
Since the mole ratio between aluminum and chlorine is 2:3, we can set up a proportion:
2 moles Al / 3 moles Cl₂ = 3.30 moles Al / x moles Cl₂
Cross-multiplying the proportions, we get:
(2 moles Al) * (x moles Cl₂) = (3.30 moles Al) * (3 moles Cl₂)
2x = 9.90
Solving for x:
x = 9.90 / 2
x = 4.95 moles Cl₂
Therefore, 4.95 moles of chlorine are needed to react with 3.30 moles of aluminum.