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A plane flying a straight course observes a mountain at a bearing of 32.6° to the right of its course. At that time the plane is 6 km from the mountain. A short time later, the bearing to the mountain becomes 42.6°. How far is the plane from the mountain when the second bearing is taken (to the nearest tenth of a km)?

  • math - ,

    11.1 km

  • math - ,

    6 sin 32.6 / sin 42.6 = 4.77

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