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Posted by on Wednesday, March 31, 2010 at 12:59pm.

At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of –0.40 rad/s^2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. What is the angular position of the wheel
at t = 2.0 s? Ans: Theta final=4.5 rad
How do you solve step by step. Thanks

  • Physics 1 (Calc Based) - , Wednesday, March 31, 2010 at 2:34pm

    angular position= 1/2 acceleraiton*time^2+ wi*time + initial position

  • Physics 1 (Calc Based) - , Wednesday, March 31, 2010 at 3:11pm

    èf = èi+ùi*t+1/2*á*t^2
    èf = 2.3rad+(1.5 rad⁄s(2.0s)+0.5(-0.40 rad⁄s^2)(2.0s)
    èf = 2.3 rad + 3.0 rad - 0.8 rad
    èf = 4.5 rad
    Thanks! Bob Pursley, This helped me solve it and here is the step by step break down.

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