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October 2, 2014

October 2, 2014

Posted by **Mariaan** on Tuesday, March 30, 2010 at 6:14am.

with the sample standard deviation equal to 3 cups. A upper limit of an approximate confidence interval

with 95% of the population average cup drunk is ?

- Stats -
**PsyDAG**, Tuesday, March 30, 2010 at 10:35am95% confidence interval = μ ± 1.96 SE

Standard Error (SE) = SD/√(n-1)

Z = (x-μ)/SE

1.96 = (x-15)/SE

Solve for x.

I hope this helps.

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