Posted by **James** on Tuesday, March 30, 2010 at 12:56am.

if a particle moves along a line so that at time t where t [0,pi] its position is given by s(t)=-4cost-t^2/2+10 what is the velocity of the particle when its acceleration is zero?

so i found

v(t) = 4sint-t

a(t)=4cost-1 = 0 solved for t plugged it into v(t) and i got the wrong answer i got 3.2 something but the choices are

-5.19

.74

1.32

2.55

8.13

please help thank you

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