Posted by Shane on Tuesday, March 30, 2010 at 12:23am.
Help with this problem please. I don't get it at all.
A ship is heading due north at 12 mph. The current is flowing southwest at 4mph. Find the actual bearing and speed of the ship.

Trig.  Reiny, Tuesday, March 30, 2010 at 8:40am
Are you studying vectors?
I see a triangle with triangle ABC with AB vertical with length 12, angle B = 45 degrees, and BC = 4
by cosine law:
b^2 = 4^2 + 12^2  2(4)(12)cos45
= 92.1177
b = 9.598
Sos the actual speed of the ship is 9.6 mph
Use the Sine Law to find angle A for the bearing
(I had 17.14 degrees)

Trig.  Alex, Wednesday, February 22, 2012 at 8:11pm
The bearing would be 36017.14= 342.86 due to the fact that the bearing scale is different than the unit circle.
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