Posted by **Shane** on Tuesday, March 30, 2010 at 12:23am.

Help with this problem please. I don't get it at all.

A ship is heading due north at 12 mph. The current is flowing southwest at 4mph. Find the actual bearing and speed of the ship.

- Trig. -
**Reiny**, Tuesday, March 30, 2010 at 8:40am
Are you studying vectors?

I see a triangle with triangle ABC with AB vertical with length 12, angle B = 45 degrees, and BC = 4

by cosine law:

b^2 = 4^2 + 12^2 - 2(4)(12)cos45

= 92.1177

b = 9.598

Sos the actual speed of the ship is 9.6 mph

Use the Sine Law to find angle A for the bearing

(I had 17.14 degrees)

- Trig. -
**Alex**, Wednesday, February 22, 2012 at 8:11pm
The bearing would be 360-17.14= 342.86 due to the fact that the bearing scale is different than the unit circle.

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