Homework Help: calc-related rates

Posted by James on Tuesday, March 30, 2010 at 12:05am.

"The volume of a cone of radius r and height h is given by V=1/2(pi)(r^2)(h)If the radius and the height both increase at a constant rate of .5 cm per second at WHAT RATE in cubic cm per second, is the volume increasing when the height is 9 cm and the radus is 6 cm"

okay so i derived the Volume equation to get

V'= (pi/3)(2r)(dr/dt)(dh/dt) and then subsituted
V' = (pi/3)(6)(2)(.5)(.5) = Pi and that is not an answer choice

the choices are

a: .5pi
b: 10pi
c: 24pi
d: 54pi
e: 108pi

thank you!

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