Posted by Thomas on .
A mixture of .10 mol of NO, .050 mol of H2 and .10 mol of H20 is
placed in a 1 liter vessel at 300 K. The following equilibrium is
2 NO + 2 H2 <----> N2 + 2 H20
At equilibrium (N0) = .062 M. What are the equilibrium concentrations
of H2 N2 and H20