posted by Carden on .
At a playground, a 18.7 kg child plays on a slide that drops through a height of 2.07 m. The child starts at rest at the top of the slide. On the way down, the slide does a nonconservative work of -318 J on the child. What is the child's speed at the bottom of the slide?
I have used v = sgrt 2gh and 1/2mv2 but to no avail.
PE at top-workdone=1/2 mv^2
I'm still confused. How does that equal 1/2mv2 and how does that solve the problem.
Starting potential energy less the work done on the way down equals the final kinetic energy.
From the final kinetic energy, you can compute the final velocity.
thank you, I got it