A 3.5-A current is maintained in a simple circuit with a total resistance of 1500 W. What net

charge passes through any point in the circuit during a thirty second interval?

current= charge/time

ampere: • noun the SI base unit of electric current, equal to a flow of one coulomb per second.

charge= 3.5coulomb/sec*30sec

To find the net charge passed through any point in the circuit during a 30-second interval, we can use the equation:

Q = I x t,

where Q is the charge, I is the current, and t is the time.

Given that the current is 3.5 A and the time is 30 seconds, we can substitute these values into the equation:

Q = 3.5 A x 30 s.

Calculating the equation, we have:

Q = 105 Coulombs.

Therefore, the net charge passed through any point in the circuit during a thirty-second interval is 105 Coulombs.

To find the net charge that passes through any point in the circuit during a thirty-second interval, you need to use the equation Q = I × t, where Q represents the charge, I represents the current, and t represents the time.

First, we need to check if the circuit is connected in series or parallel. If it is connected in series, the current will be the same throughout the entire circuit. If it is connected in parallel, the current will split between the different branches of the circuit.

Based on the information given, we can assume that the circuit is connected in series since the current is maintained throughout the circuit.

Now, we can use the given information to calculate the charge. The current is given as 3.5 A, and the time interval is thirty seconds (t = 30 s).

Q = I × t
Q = 3.5 A × 30 s

Calculating this equation will give you the net charge that passes through any point in the circuit during the thirty-second interval.