Posted by Felicity on Monday, March 29, 2010 at 6:41pm.
Alright, so I'm doing questions on exponent laws for my grade 11 math couse, and I came across one and I've no idea how to answer it. Could someone please explain step by step? According to textbook, answer should be 16:
(2^3) / [(2^0)(2^1)]
That "1" is a negative exponent in the last bit, just so you know.

Maths  MathMate, Monday, March 29, 2010 at 7:08pm
Some of the exponential laws state that:
a^{0}=1
a^{1}=a
a^{b}=1/a^{b}
In your case, a=2 (the base).
So these laws should enable you to evaluate each term of the denominator.
The answer should indeed be 16.
I appreciate your having inserted sufficient parentheses to render the expression unambiguous.

Maths  Felicity, Monday, March 29, 2010 at 7:14pm
I hope I'm not asking too much, but it would be ace if you would type out the problem and the path to solving it just so I can compare and see where I'm going wrong?

Maths  MathMate, Monday, March 29, 2010 at 7:56pm
Here it is. Post if help is needed.
(2^3) / [(2^0)(2^1)]
=8/(2^02^1)
=8/(1 1/2¹)
=8/(1 1/2)
=8/(1/2)
=16
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