Friday

July 25, 2014

July 25, 2014

Posted by **Help now fast due tommorow!!!!!!!!!!!!!!!!!!!!!!!!** on Monday, March 29, 2010 at 6:36pm.

A) 256.5 feet b) 258 feet

c) 256 feet d) 257 feet

please show work!

i need help fast

- Precalculus -
**MathMate**, Monday, March 29, 2010 at 6:47pmLet L=total length of fencing.

x=width

(L/2-x)=length

A(x)=Area=x(L/2-x)

Differentiate A with respect to x, and equate A'(x) to zero and solve for x=x0 which gives the maximum or minimum area.

Differentiate A'(x) again to get A"(x).

Confirm that A"(x0) is negative for a maximum (and positive for a minimum).

You should find that x0=width=length.

Post your answer for a check if you wish.

- Precalculus -
**Help now fast due tommorow!!!!!!!!!!!!!!!!!!!!!!!!**, Monday, March 29, 2010 at 9:50pmis it 258

- Precalculus -
**MathMate**, Tuesday, March 30, 2010 at 9:39pmYes, that's correct.

**Related Questions**

Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose ...

Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose...

Precalculus help fast - a farmer has available 1032 feet of fencing and wishes ...

Algebra - A farmer plans to enclose a rectangular region using part of his barn ...

pre-calc - area of a rectangular region: a farmer wishes to create two ...

Calculus - A pig farmer wants to enclose a rectangular area and then divide it ...

Calculus - A ostrich farmer wants to enclose a rectangular area and then divide ...

ALGEBRA - A farmer has 165 feet of fencing material in which to enclose a ...

Calculus - A farmer wishes to enclose a long rectangular pin that will then be ...

calculus - a farmer has a 1500 feet of fencing in his barn.he wishes to enclose ...