Posted by **Anonymous** on Monday, March 29, 2010 at 6:29pm.

a 3.5 kg dog stands on a 21 kg flatboat at distance D = 6.1 m from the shore. It walks 2.3 m along the boat toward shore and then stops. Assuming no friction between the boat and the water, find how far the dog is then from the shore.

I thought i have the right equation but my answer is not correct.

dog moves 2.3(3.5/21) m toward the shore

then you would subtract the overall distance and the answer above? right?

so 6.1 - .38 = 5.72 which is incorrect.

A little help please?

## Answer This Question

## Related Questions

- Physics - a 3.7 kg dog stands on a 19 kg flatboat at distance D = 6.1 m from the...
- physics help - a 3.5 kg dog stands on a 21 kg flatboat at distance D = 6.1 m ...
- Physics - A dog, with a mass of 8.0 kg, is standing on a flatboat so that he is ...
- Physics - A dog, weighing 10.0 lbs, is standing on a flatboat so that he is 20 ...
- Physics - A 63 kg canoeist stands in the middle of her 19 kg canoe. The canoe is...
- physics - a person of mass 80 kg standing on a boat of mass 320 kg which at rest...
- Physics - a boat crosses a 2 km wide river by starting out at the south shore ...
- Physics - a boat crosses a 2 km wide river by starting out at the south shore ...
- Physics - Two boats are heading away from shore. Boat 1 heads due north at a ...
- Physics - Two boats are heading away from shore. Boat 1 heads due north at a ...

More Related Questions