Homework Help: physics help!!

Posted by Anonymous on Monday, March 29, 2010 at 6:29pm.

a 3.5 kg dog stands on a 21 kg flatboat at distance D = 6.1 m from the shore. It walks 2.3 m along the boat toward shore and then stops. Assuming no friction between the boat and the water, find how far the dog is then from the shore.

I thought i have the right equation but my answer is not correct.

dog moves 2.3(3.5/21) m toward the shore

then you would subtract the overall distance and the answer above? right?

so 6.1 - .38 = 5.72 which is incorrect.

A little help please?

No one has answered this question yet.

Answer this Question

Related Questions

physics help - a 3.5 kg dog stands on a 21 kg flatboat at distance D = 6.1 m ...
Physics - a 3.7 kg dog stands on a 19 kg flatboat at distance D = 6.1 m from the...
Physics - A dog, with a mass of 8.0 kg, is standing on a flatboat so that he is ...
physics - The following objects are released from rest and allowed to roll down ...
Physics - A man of mass 65.2 kg stands on a scaffold supported by a vertical ...
physics - A man of mass 67.1 kg stands on a scaffold supported by a vertical ...
physics - A man of mass 61.6 kg stands on a scaffold supported by a vertical ...
Physics - A man of mass 64.8 kg stands on a scaffold supported by a vertical ...
Physics - A man of mass 64.8 kg stands on a scaffold supported by a vertical ...
Physics - A man of mass 65.2 kg stands on a scaffold supported by a vertical ...

For Further Reading

First Name:
School Subject:
Answer: