Post a New Question


posted by on .

Scores on a test have a mean of 66 and Q3 of 81. The scores have a distribution that is approximately normal. Find the standard deviation. Round your answer to the nearest tenth.

  • statistics - ,

    Q3 = 75 percentile

    In a table in the back of your stat book labeled something like "areas under normal distribution," find the Z score equivalent. Put value in formula below.

    Z = (x - μ)/ SD = (81-66)/SD

    Solve for SD.

  • statistics - ,

    (81-66)/SD = 0.67(z score of 0.75)
    15/SD= 0.67

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question