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Physics force of friction question

a 63kg water skier is pulled across a lake by a rope that exerts a force of 3.2x10^2 and makes an angle 17 degrees above the horizontal. if the coefficient between the skies and the lake is 0.27 at what rate will the skier accelerate?

  • physics - ,

    acceleration = (Net horizontal force)/Mass
    = (320 cos 17 - M g *0.27)/M
    = 306/M -0.27 g = (4.86 - 2.65)
    = 2.21 m/s^2

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