Posted by **Kate** on Sunday, March 28, 2010 at 10:19pm.

[b]1. The problem statement, all variables and given/known data[/b]

The average growth rate of the population of a certain city is 7.5% per year. The city's population is now 22,750 people. What is the expected population in 10 years?

[b]2. Relevant equations[/b]

I was always taught this formula for exponential growth

N(t) = N_0 e^(kt)

N = population

N_0 = population at t(0)

e = 2.7...

k = some positive constant

t = time

Here's what my teacher wrote on my paper for the formula

f(x) = C(1 + r)^x

f(x) = population

C = initial population

r = growth rate

[b]3. The attempt at a solution[/b]

no i dont understand how to do this exactly because I don't know what to use for the constant k

so i used the second one

22750 (1 + .075)^10 = 46888.4680

now what I don't udnerstand is that this really makes no sense at all becasue if I wanted to fidn the population at 10 minutes or ten centuries and just plugged in 10 into the equation with no units at all I would get the same exact answer. Can youp please tell me how to go about reasoning this out... THANKS!

- PreCalc -
**Reiny**, Sunday, March 28, 2010 at 11:25pm
When your teacher wrote ...

f(x) = C(1 + r)^x

f(x) = population

C = initial population

r = growth rate

he/she should have also defined x to be the annual rate.

so when you replaced x with 10 it was understood that it was years, since the r was the rate per year

If you wanted to find out for a time other than years, you would have to change t to that fraction of a year.

e.g. if you only wanted it for 10 months, t = 10/12 or .83333..

if you wanted 10 minutes you would have to find the number of minutes in a year

which is 365*24*60 = 525600

so your exponent for 10 minutes would not be 10 but

10/525600

the second equation is probably the easier to use for these types of questions.

you could use the first one

N(t) = N_{0} e^(kt)

here we have to find the value of k first by using one set of data given, that is

when t = 1,

22750(1.075) = 22750e^1k)

e^k = 1.075

k = ln 1.075 = .07232

so N(t) = 22750e^.07232t

so when t=10

N(10) = 22750(e^(.07232)(10))

= 46888.46804 exactly the same as obtained with the other formula.

## Answer this Question

## Related Questions

- Alegbra - 12. A city whose population was 39,350 in 1995 contained 46,750 people...
- TRIG - the population of a certain city is 1.3 million people. if the population...
- Math - a. Do some research and find a city that has experienced population ...
- Algebra word problem help - The average walking speed R of people living in a ...
- college algebra HELP - The population of a city was 166 thousand at the begining...
- Uninhibited Growth - In 1992, Chad and Denmark each had a population of about 5....
- exponential equations - The City of South Bay has a current population of 85 000...
- exponential equations - The City of South Bay has a current population of 85 000...
- Math - The population of New York doubles during the workday. At the end of the ...
- Algebra 1 - The population of a city increases by 4,000 people each year. In ...

More Related Questions