Posted by **sara** on Sunday, March 28, 2010 at 9:03pm.

A ball of mass 0.075 kg is fired horizontally into a ballistic pendulum. The pendulum mass is 0.350 kg. The ball is caught in the pendulum, and the centerof mass of the system rises a vertical distance of 0.145 m in the earth's gravitational field. What was the original speed of the ball? Assume g=9.80 m/s^2. How much kinetic energy was lost in the collision?

- physics -
**drwls**, Monday, March 29, 2010 at 12:33am
The distance than the block rises with the ball inside will tell you the velocity right after impact (V2), using conservation of energy.

V2 = sqrt (2gH); H = 0.145 m

Once you have determined V2, get the original speed of the ball (V1) by using conservation of momentum.

m V1 = (M+m) V2

Once you know v and V, calculatring the loss of kinetic energy is easy.

KE loss = (1/2)m V1^2 - (1/2)(m+M)V2^2

## Answer This Question

## Related Questions

- physics - A ball of mass 0.075 kg is fired horizontally into a ballistic ...
- Physics - A bullet of mass 3.2 g strikes a ballistic pendulum of mass 3.6 kg. ...
- physics - A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The ...
- physics for physical science - a bullet of mass 0.015kg strikes ballistic ...
- Physics - In a ballistic pendulum experiment, a small marble is fired into a cup...
- Physics - A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. ...
- physics - A ballistic pendulum consists of a rectangular wooden block of mass 1....
- Physics- Ballistic pendulum - A simple pendulum is made from a 2 kg. block of ...
- physics - A(n) 3.46 g bullet is fired into a(n) 2.4 kg ballistic pendulum and ...
- Physics - A(n) 5.52 g bullet is fired into a(n) 3.07 kg ballistic pendulum and ...

More Related Questions