7x+5y=-26
x=28-6y
solve using substitution
okay so then 196-42y+5y=-26
then combined like terms so
196+37y=-26
37y=-222
y=-6 is this part correct?
You are correct KiKi. y= -6
I believe that is a +6 and most would prefer that you put in another step.
like so:
7(28 - 6y) + 5y = -26, then
196 -42y + 5y = -26
-37y = -222
y=+6
You are correct. The answer is -6.
7(28-6y)+5y=-26
196-42y+5y=-26
37y=-222
37y/37=-222/37
y=-6
The answer is not -6, it is +6.
Both Louise and Michael subtracted incorrectly.
7(28-6y) + 5y = -26
196-42y + 5y = -26
(-42y + 5y is -37y; therefore)
196 - 37y = -26-196 = -222
-37y= -222 and
y=(-222/-37) = +6.
Solve for x now.
x = 28-6y
x = 28-6(+6)
x = 28-36
x - -8.
Now substitute x = -8 and y = +6 into the first equation.
7x + 5y = -26
7(-8) + 5(+6) = -26
-56 + 30 = -26
-26 = -26
Substitute -6 and it won't work.
0y-5-5y=6y-6-26
To solve the system of equations using substitution, we substitute the expression for x from one equation into the other equation.
Given:
1) 7x + 5y = -26
2) x = 28 - 6y
Substitute x from equation 2) into equation 1):
7(28 - 6y) + 5y = -26
196 - 42y + 5y = -26
Now, combine like terms:
-37y + 196 = -26
To solve for y, subtract 196 from both sides:
-37y = -26 - 196
-37y = -222
Now, divide both sides by -37 to solve for y:
y = -222 / -37
y = 6
So, the solution is y = 6.
To find the value of x, substitute y = 6 into either of the original equations. Let's use equation 2):
x = 28 - 6(6)
x = 28 - 36
x = -8
Therefore, the solution to the system of equations is x = -8 and y = 6.