Sunday
November 23, 2014

Homework Help: Chem

Posted by Katie on Sunday, March 28, 2010 at 8:03pm.

Aspirin (acetylsalicylic acid, ) is a weak monoprotic acid. To determine its acid-dissociation constant, a student dissolved 2.00 g of aspirin in 0.600 L of water and measured the pH . What was the Ka value calculated by the student if the of the pH of the solution was 2.62?

I know that Ka =[h3O+][a-]/[ha] but i don't know how to solve this.

so far i have
[h3o+]=-log(2.62)=2.4*10^-3
and
[oh-]=4.17*10-12

but i'm not sure what exactly this question is looking for. if you could point me in the right direction that would be great. thank you.

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