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April 1, 2015

April 1, 2015

Posted by **jh** on Sunday, March 28, 2010 at 7:30pm.

pi < theta < 3pi/2

Find:

sin(theta)= -1 ?

cos(theta)= -3 ?

tan(theta)= 1/3 ?

sec(theta)= -1/3 ?

csc(theta)= -1 ?

That's what I came up with, but they are not correct, PLEASE help me where I went wrong!!

- Precalculus(NEED HELP ASAP PLEASE!!) -
**bobpursley**, Sunday, March 28, 2010 at 7:34pmtan theta= 1/3 which means sintheta 1/sqr10

draw the triangle Notice it is in the third quadrant, where cosine is negative.

- Precalculus(NEED HELP ASAP PLEASE!!) -
**Damon**, Sunday, March 28, 2010 at 7:45pmYou do not seem to have calculated the hypotenuse which you need for sin and cos and sec and csc

sqrt (1^2+3^2) = sqrt 10

- Precalculus(NEED HELP ASAP PLEASE!!) -
**jh**, Sunday, March 28, 2010 at 7:47pmSo,

tan(theta)=sin(theta)/cos(theta)

cos(theta)=sin(theta)/tan(theta)

=(1/sqrt(10))/(1/3)

= 3/sqrt(10) ??

But its incorrect!! What am I doing wrong?

- Precalculus(NEED HELP ASAP PLEASE!!) -
**Josie**, Tuesday, February 22, 2011 at 3:12pmIf sin t=-1/4, find sin t + 6pi

- Precalculus(NEED HELP ASAP PLEASE!!) -
**Kayla**, Sunday, March 29, 2015 at 6:07pmtan theta= 5 divided by 12 and theta is in quadrant 3 what does sin 2 theta equal

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