Posted by jh on Sunday, March 28, 2010 at 7:30pm.
cot(theta)= 3
pi < theta < 3pi/2
Find:
sin(theta)= 1 ?
cos(theta)= 3 ?
tan(theta)= 1/3 ?
sec(theta)= 1/3 ?
csc(theta)= 1 ?
That's what I came up with, but they are not correct, PLEASE help me where I went wrong!!

Precalculus(NEED HELP ASAP PLEASE!!)  bobpursley, Sunday, March 28, 2010 at 7:34pm
tan theta= 1/3 which means sintheta 1/sqr10
draw the triangle Notice it is in the third quadrant, where cosine is negative.

Precalculus(NEED HELP ASAP PLEASE!!)  Damon, Sunday, March 28, 2010 at 7:45pm
You do not seem to have calculated the hypotenuse which you need for sin and cos and sec and csc
sqrt (1^2+3^2) = sqrt 10

Precalculus(NEED HELP ASAP PLEASE!!)  jh, Sunday, March 28, 2010 at 7:47pm
So,
tan(theta)=sin(theta)/cos(theta)
cos(theta)=sin(theta)/tan(theta)
=(1/sqrt(10))/(1/3)
= 3/sqrt(10) ??
But its incorrect!! What am I doing wrong?

Precalculus(NEED HELP ASAP PLEASE!!)  Josie, Tuesday, February 22, 2011 at 3:12pm
If sin t=1/4, find sin t + 6pi

Precalculus(NEED HELP ASAP PLEASE!!)  Kayla, Sunday, March 29, 2015 at 6:07pm
tan theta= 5 divided by 12 and theta is in quadrant 3 what does sin 2 theta equal
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