Posted by Phillip on Sunday, March 28, 2010 at 6:55pm.
divide one equation by the other
4=e^2k solve for k. Put it back in, and solve for P(O)
There is an easier way. From the data, one can see that population doubles each hour.
Sure, use y = Po e^kt
when t = 3:
10,000 = Po e^3k
ln 10,000 = ln Po + 3k ln e but ln e is 1
ln 10,000 = ln Po + 3 k
ln 40,000 = ln Po + 5 k
ln 10,000 -ln 40,000 = -2 k
ln (10,000/40,000) = -2k
-1.386 = -2k
k = .693
10,000 = Po e^(2.0794)
Po = 1250
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