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October 24, 2014

October 24, 2014

Posted by **claudia** on Saturday, March 27, 2010 at 6:55pm.

concentrated on the outside radius. Assume that you apply a force F to a sprocket so that the wheel

has an angular acceleration ® = 4:50 rad/s2. A resistive force f = 131 N is applied to the rim of the

tire when it is moving.

calculate the strength of the required

force F, when the radius r is:

(a) 4.53 cm.

I worked out the problems using the sum of the Torque=I@

I@=-rFsin90+Rfsin90

Then I solved for F but my answer is 40 Newtons away from the right answer which is 940 N.

There is a picture of the problem in google if you just paste the entire problem on the search space it brings out a pdf file that has the picture it is problem 10-8

- Physics 121 -
**bobpursley**, Saturday, March 27, 2010 at 7:17pmmr^2*4.5=r*F-131*.16

1.80*..32^2*4.5=.0453*F-131*.32

I get 940

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