Posted by Edwin on .
An open tank holds water 1.25 m deep. If a small hole of cross section area 3cm^2 is made at the bottom of the tank, calculate the mass of water per second initially flowing out of the hole. (g=10m/s^2, density of water= 1000 kgm^3)

physics 
drwls,
Sice you are still showing no work, my advice will be brief.
Use the Bernoulli equation (with altitude change)to get the velocity and the continuity equation to get the mass flow rate. 
physics 
blessing,
Don't know how to solve it!pleas help me out

Physics 
John Cena,
Mass of water flowing out per second = mv
v is the velocity of the water coming out of the hole.
Since 'm' = V¶
Where 'V' is the volume of hole
'¶' is the density of water flowing out.
Therefore,mass of water flowing out per second= 0.03*1000*√2*10*1.25
=150kg/sec