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December 22, 2014

December 22, 2014

Posted by **stacey graham** on Saturday, March 27, 2010 at 9:21am.

- trig -
**Reiny**, Saturday, March 27, 2010 at 10:32amWriting everything in terms of sine and cosine usually works, so ...

LS = (sinx/cosx + cosx/sinx)/(sinx/cosx - cosx/sinx)

= [(sin^2x + cos^2x)/sinxcosx]/[(sin^2x - cos^2x)/(sinxcosx)]

= [(sin^2x + cos^2x)/sinxcosx][(sinxcosx0)/(sin^2x - cos^2x)]

= 1/(sin^2x - cos^2x)

= RS

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