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January 29, 2015

January 29, 2015

Posted by **Hannah** on Friday, March 26, 2010 at 5:30pm.

g(x) = 4 [x-2] / x + 1

My answer was there are two horizontal asymptotes. My teacher said that there are two asymptotes but she wants me to find the equation for them. I do not understand what she means.

- I tried to answer earlier. Use parentheses -
**Damon**, Friday, March 26, 2010 at 5:37pmIf x is alone at the bottom, you have vertical asymptotes at x = 0

if (x+1) is on the bottom, they are at x = -1

There are no horizontal asymptotes here.

- Pre-Cal -
**Damon**, Friday, March 26, 2010 at 5:39pmx = 0 is the equation of a vertical asymptote for example, graph it.

- Pre-Cal -
**Reiny**, Friday, March 26, 2010 at 5:42pmI have to disagree with Damon, although he is usually right.

If your equation is

y = 4(x-2)/(x+1) there is a horizontal asymptote of

y = 4

If you equation is

y = 4(x-2)/x + 1 as you typed it,

there is a horizontal asymptote of

y = 5

- Pre-Cal -
**Damon**, Friday, March 26, 2010 at 5:49pmSorry. I only really looked at the x singularity.

Of course if x gets big positive or negative y approaches 4 (x/x) if you have (x-2)/(x+1)

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