Monday

December 22, 2014

December 22, 2014

Posted by **stacey graham** on Friday, March 26, 2010 at 9:30am.

- trig -
**LiNnda**, Monday, May 3, 2010 at 10:52amtan^2x(1+cot^x)=1/(1-sin^2x)

tan^2x(1+1/tan^2x)=1/cos^2x

tan^2x+(tan^x/tan^2x)=1/cos^2x

tan^2x+1=1/cos^2x

sin^2x/cos^2x+1=1/cos^2x

(sin^x+cos^2)/cos^2x=1/cos^2x

1/cos^2x=1/cos^2x

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