Posted by stacey graham on Friday, March 26, 2010 at 12:24am.
if cosA = 1/3 in I, then sinA = √8/3 using Pythagoras
if sinB= -1/2 in IV, the cosB = √3/2
sin (A-B) = sinAcosB - cosAsinB
= (√8/3)(√3/2) - (1/3)(-1/2)
= (√24 + 1)/6
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