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August 27, 2014

August 27, 2014

Posted by **stacey graham** on Friday, March 26, 2010 at 12:16am.

tan^2x(1+cot^2x)=1/1-sin^2x

Verify the Id:

tanx + cotx/ tanx-cotx = (1/sin^2x-cos^2x)

- trig -
**Damon**, Friday, March 26, 2010 at 7:35am(s^2/c^2)( 1+ c^2/s^2) = ? 1/(1-s^2)

s^2/c^2 + 1 = ? 1/(c^2)

(s^2+c^2)/c^2 = = ? 1/(c^2)

1/c^2 = 1/c^2

- needs parentheses -
**Damon**, Friday, March 26, 2010 at 7:50amtanx + cotx/ tanx-cotx = (1/sin^2x-cos^2x)

I can not tell what the numerators and denominators are.

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