Posted by mona on Thursday, March 25, 2010 at 11:24pm.
at t=5
A west of origin 20+21*5 = 125 or x=-125
B north of origin = 18*5 = 90 or y = 90
h^2 = x^2+y^2
h=(x^2+y^2)^.5 = 154 where h is hypotenuse
we want dh/dt
2 h dh/dt = 2 x dx/dt + 2 y dy/dt
2(154) dh/dt = 2(-125)(-21) + 2 (90)(18)
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