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Posted by on Thursday, March 25, 2010 at 5:00pm.

What is the angular momentum of a 2.5 kg uniform cylindrical grinding wheel of radius 19 cm when rotating at 1200 rpm? And how much torque is required to stop it in 5.7 s? Need help with step-by-step explanation.

  • physics help please!!! - , Thursday, March 25, 2010 at 5:39pm

    chose your moment of Inertia model. I think solid disk is a good model. I= 1/2 mr^2

    angMomentum= I*angvelocity

    where w (angular velocity)=2PI*1200/60 rad /seconds

    Torque=momentinertia*angularacceleration
    = 1/2 m r^2 * change in angvelocity/time
    = 1/2 m r^2 * (wf-wi)/5.7sec

    wf=0 ; wi is 2PI*1200/60 rad/sec

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